List Construction
Posted: 9 Nov 2022 20:30
I remember seeing somewhere an abbreviated method to construct a list of sequential integers.
I am looking for:
to be achieved with a shortcut looking something like this
But, I can not remember or find the proper syntax for that abbreviated method.
I am looking for:
Code: Select all
List=[1,2,3,4,5]
Code: Select all
List=[1..5]