syntaxError_exception (pfc\pie\pie)
Posted: 7 Oct 2015 17:04
I am getting the following exception on the line of code in 64-bit.
not(list::isMember("ABC", ["DEF", "GHI"])),
During the debugging, I saw the exact values in "Variables in the current clause" view.
The code did not raise any exception in 32-bit.
Any idea?
Exception: syntaxError_exception (pfc\pie\pie)
PIE syntax error
Predicate name = maketok
SourceCursor = pfc\pie\scanner\scanner.pro(173,9)
cursor = 67
Arguments = Illegal token: '0xDC207BE160'
raised 2015-10-07 12:44:03
ThreadId: 6080
Class name: pfc\pie\scanner
Predicate name: maketok
not(list::isMember("ABC", ["DEF", "GHI"])),
During the debugging, I saw the exact values in "Variables in the current clause" view.
The code did not raise any exception in 32-bit.
Any idea?
Exception: syntaxError_exception (pfc\pie\pie)
PIE syntax error
Predicate name = maketok
SourceCursor = pfc\pie\scanner\scanner.pro(173,9)
cursor = 67
Arguments = Illegal token: '0xDC207BE160'
raised 2015-10-07 12:44:03
ThreadId: 6080
Class name: pfc\pie\scanner
Predicate name: maketok